43/4x+2/5x=7/40

Solution for 43/4x+2/5x=7/40 equation:

43/4x+2/5x=7/40

We move all terms to the left:

43/4x+2/5x-(7/40)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

43/4x+2/5x-(+7/40)=0

We get rid of parentheses

43/4x+2/5x-7/40=0

We calculate fractions


(-700x^2)/3200x^2+34400x/3200x^2+1280x/3200x^2=0

We multiply all the terms by the denominator


(-700x^2)+34400x+1280x=0

We add all the numbers together, and all the variables

(-700x^2)+35680x=0

We get rid of parentheses

-700x^2+35680x=0

a = -700; b = 35680; c = 0;
Δ = b2-4ac
Δ = 356802-4·(-700)·0
Δ = 1273062400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1273062400}=35680$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35680)-35680}{2*-700}=\frac{-71360}{-1400}
=50+34/35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35680)+35680}{2*-700}=\frac{0}{-1400}
=0
$