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(6x+4)(9x-4)=180
We move all terms to the left:
(6x+4)(9x-4)-(180)=0
We multiply parentheses ..
(+54x^2-24x+36x-16)-180=0
We get rid of parentheses
54x^2-24x+36x-16-180=0
We add all the numbers together, and all the variables
54x^2+12x-196=0
a = 54; b = 12; c = -196;
Δ = b2-4ac
Δ = 122-4·54·(-196)
Δ = 42480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{42480}=\sqrt{144*295}=\sqrt{144}*\sqrt{295}=12\sqrt{295}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{295}}{2*54}=\frac{-12-12\sqrt{295}}{108} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{295}}{2*54}=\frac{-12+12\sqrt{295}}{108} $
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