41=7(3b+2)+3(-5b+1)

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Solution for 41=7(3b+2)+3(-5b+1) equation: 



41=7(3b+2)+3(-5b+1)

We move all terms to the left:

41-(7(3b+2)+3(-5b+1))=0



We calculate terms in parentheses: -(7(3b+2)+3(-5b+1)), so:

7(3b+2)+3(-5b+1)

We multiply parentheses

21b-15b+14+3

We add all the numbers together, and all the variables

6b+17

Back to the equation:

-(6b+17)



We get rid of parentheses

-6b-17+41=0

We add all the numbers together, and all the variables

-6b+24=0

We move all terms containing b to the left, all other terms to the right

-6b=-24

b=-24/-6

b=+4

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