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10(x+3)+6=2(5x+18)
We move all terms to the left:
10(x+3)+6-(2(5x+18))=0
We multiply parentheses
10x-(2(5x+18))+30+6=0
We calculate terms in parentheses: -(2(5x+18)), so:We add all the numbers together, and all the variables
2(5x+18)
We multiply parentheses
10x+36
Back to the equation:
-(10x+36)
10x-(10x+36)+36=0
We get rid of parentheses
10x-10x-36+36=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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