3(23-2b)=48-3b

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Solution for 3(23-2b)=48-3b equation: 



3(23-2b)=48-3b

We move all terms to the left:

3(23-2b)-(48-3b)=0

We add all the numbers together, and all the variables

3(-2b+23)-(-3b+48)=0

We multiply parentheses

-6b-(-3b+48)+69=0

We get rid of parentheses

-6b+3b-48+69=0

We add all the numbers together, and all the variables

-3b+21=0

We move all terms containing b to the left, all other terms to the right

-3b=-21

b=-21/-3

b=+7

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