41=(5n-6)/2+41-(5n-6)2

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Solution for 41=(5n-6)/2+41-(5n-6)2 equation: 



41=(5n-6)/2+41-(5n-6)2

We move all terms to the left:

41-((5n-6)/2+41-(5n-6)2)=0



Domain of the equation: 2+41-(5n-6)2)!=0

We move all terms containing n to the left, all other terms to the right

-(5n-6)2)!=-43

n∈R



We multiply all the terms by the denominator


-((5n-6)+41*2+41-(5n-6)2)=0



We calculate terms in parentheses: -((5n-6)+41*2+41-(5n-6)2), so:

(5n-6)+41*2+41-(5n-6)2

determiningTheFunctionDomain
(5n-6)-(5n-6)2+41+41*2

We add all the numbers together, and all the variables

(5n-6)-(5n-6)2+123

We multiply parentheses

(5n-6)-10n+12+123

We get rid of parentheses

5n-10n-6+12+123

We add all the numbers together, and all the variables

-5n+129

Back to the equation:

-(-5n+129)



We get rid of parentheses

5n-129=0

We move all terms containing n to the left, all other terms to the right

5n=129

n=129/5

n=25+4/5

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