41=(5n+6)/2+41-(5n+6)2

Solution for 41=(5n+6)/2+41-(5n+6)2 equation:

41=(5n+6)/2+41-(5n+6)2

We move all terms to the left:

41-((5n+6)/2+41-(5n+6)2)=0


Domain of the equation: 2+41-(5n+6)2)!=0

We move all terms containing n to the left, all other terms to the right

-(5n+6)2)!=-43

n∈R


We multiply all the terms by the denominator


-((5n+6)+41*2+41-(5n+6)2)=0


We calculate terms in parentheses: -((5n+6)+41*2+41-(5n+6)2), so:

(5n+6)+41*2+41-(5n+6)2

determiningTheFunctionDomain
(5n+6)-(5n+6)2+41+41*2

We add all the numbers together, and all the variables

(5n+6)-(5n+6)2+123

We multiply parentheses

(5n+6)-10n-12+123

We get rid of parentheses

5n-10n+6-12+123

We add all the numbers together, and all the variables

-5n+117

Back to the equation:

-(-5n+117)


We get rid of parentheses

5n-117=0

We move all terms containing n to the left, all other terms to the right

5n=117

n=117/5

n=23+2/5