6(x+1)=4(x-3)

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Solution for 6(x+1)=4(x-3) equation: 



6(x+1)=4(x-3)

We move all terms to the left:

6(x+1)-(4(x-3))=0

We multiply parentheses

6x-(4(x-3))+6=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

6x-4x+12+6=0

We add all the numbers together, and all the variables

2x+18=0

We move all terms containing x to the left, all other terms to the right

2x=-18

x=-18/2

x=-9

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