41+7x-19=-3(2+x-4x)

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Solution for 41+7x-19=-3(2+x-4x) equation: 



41+7x-19=-3(2+x-4x)

We move all terms to the left:

41+7x-19-(-3(2+x-4x))=0

We add all the numbers together, and all the variables

7x-(-3(-3x+2))+41-19=0

We add all the numbers together, and all the variables

7x-(-3(-3x+2))+22=0



We calculate terms in parentheses: -(-3(-3x+2)), so:

-3(-3x+2)

We multiply parentheses

9x-6

Back to the equation:

-(9x-6)



We get rid of parentheses

7x-9x+6+22=0

We add all the numbers together, and all the variables

-2x+28=0

We move all terms containing x to the left, all other terms to the right

-2x=-28

x=-28/-2

x=+14

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