20=2(v+4)+4v

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Solution for 20=2(v+4)+4v equation: 



20=2(v+4)+4v

We move all terms to the left:

20-(2(v+4)+4v)=0



We calculate terms in parentheses: -(2(v+4)+4v), so:

2(v+4)+4v

We add all the numbers together, and all the variables

4v+2(v+4)

We multiply parentheses

4v+2v+8

We add all the numbers together, and all the variables

6v+8

Back to the equation:

-(6v+8)



We get rid of parentheses

-6v-8+20=0

We add all the numbers together, and all the variables

-6v+12=0

We move all terms containing v to the left, all other terms to the right

-6v=-12

v=-12/-6

v=+2

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