40=4y-6(2y-4)

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Solution for 40=4y-6(2y-4) equation: 



40=4y-6(2y-4)

We move all terms to the left:

40-(4y-6(2y-4))=0



We calculate terms in parentheses: -(4y-6(2y-4)), so:

4y-6(2y-4)

We multiply parentheses

4y-12y+24

We add all the numbers together, and all the variables

-8y+24

Back to the equation:

-(-8y+24)



We get rid of parentheses

8y-24+40=0

We add all the numbers together, and all the variables

8y+16=0

We move all terms containing y to the left, all other terms to the right

8y=-16

y=-16/8

y=-2

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