17-5(7-9x)=8(6x+1)-3

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Solution for 17-5(7-9x)=8(6x+1)-3 equation:



17-5(7-9x)=8(6x+1)-3
We move all terms to the left:
17-5(7-9x)-(8(6x+1)-3)=0
We add all the numbers together, and all the variables
-5(-9x+7)-(8(6x+1)-3)+17=0
We multiply parentheses
45x-(8(6x+1)-3)-35+17=0
We calculate terms in parentheses: -(8(6x+1)-3), so:
8(6x+1)-3
We multiply parentheses
48x+8-3
We add all the numbers together, and all the variables
48x+5
Back to the equation:
-(48x+5)
We add all the numbers together, and all the variables
45x-(48x+5)-18=0
We get rid of parentheses
45x-48x-5-18=0
We add all the numbers together, and all the variables
-3x-23=0
We move all terms containing x to the left, all other terms to the right
-3x=23
x=23/-3
x=-7+2/3

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