5(y-3)+2=3(y+1)

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Solution for 5(y-3)+2=3(y+1) equation: 



5(y-3)+2=3(y+1)

We move all terms to the left:

5(y-3)+2-(3(y+1))=0

We multiply parentheses

5y-(3(y+1))-15+2=0



We calculate terms in parentheses: -(3(y+1)), so:

3(y+1)

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)



We add all the numbers together, and all the variables

5y-(3y+3)-13=0

We get rid of parentheses

5y-3y-3-13=0

We add all the numbers together, and all the variables

2y-16=0

We move all terms containing y to the left, all other terms to the right

2y=16

y=16/2

y=8

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