40=-5(4z-8)+20z

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Solution for 40=-5(4z-8)+20z equation: 



40=-5(4z-8)+20z

We move all terms to the left:

40-(-5(4z-8)+20z)=0



We calculate terms in parentheses: -(-5(4z-8)+20z), so:

-5(4z-8)+20z

We add all the numbers together, and all the variables

20z-5(4z-8)

We multiply parentheses

20z-20z+40

We add all the numbers together, and all the variables

40

Back to the equation:

-(40)



We add all the numbers together, and all the variables

=0

z=0/1

z=0

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