5(t-4)+7t=6(2t+5)-13

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Solution for 5(t-4)+7t=6(2t+5)-13 equation: 



5(t-4)+7t=6(2t+5)-13

We move all terms to the left:

5(t-4)+7t-(6(2t+5)-13)=0

We add all the numbers together, and all the variables

7t+5(t-4)-(6(2t+5)-13)=0

We multiply parentheses

7t+5t-(6(2t+5)-13)-20=0



We calculate terms in parentheses: -(6(2t+5)-13), so:

6(2t+5)-13

We multiply parentheses

12t+30-13

We add all the numbers together, and all the variables

12t+17

Back to the equation:

-(12t+17)



We add all the numbers together, and all the variables

12t-(12t+17)-20=0

We get rid of parentheses

12t-12t-17-20=0

We add all the numbers together, and all the variables

-37!=0

There is no solution for this equation

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