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14=6x^2-17x
We move all terms to the left:
14-(6x^2-17x)=0
We get rid of parentheses
-6x^2+17x+14=0
a = -6; b = 17; c = +14;
Δ = b2-4ac
Δ = 172-4·(-6)·14
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-25}{2*-6}=\frac{-42}{-12} =3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+25}{2*-6}=\frac{8}{-12} =-2/3 $
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