3(x-3)=2x-(3+x)

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Solution for 3(x-3)=2x-(3+x) equation: 



3(x-3)=2x-(3+x)

We move all terms to the left:

3(x-3)-(2x-(3+x))=0

We add all the numbers together, and all the variables

3(x-3)-(2x-(x+3))=0

We multiply parentheses

3x-(2x-(x+3))-9=0



We calculate terms in parentheses: -(2x-(x+3)), so:

2x-(x+3)

We get rid of parentheses

2x-x-3

We add all the numbers together, and all the variables

x-3

Back to the equation:

-(x-3)



We get rid of parentheses

3x-x+3-9=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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