3(x-3)=2x-(2+x)

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Solution for 3(x-3)=2x-(2+x) equation: 



3(x-3)=2x-(2+x)

We move all terms to the left:

3(x-3)-(2x-(2+x))=0

We add all the numbers together, and all the variables

3(x-3)-(2x-(x+2))=0

We multiply parentheses

3x-(2x-(x+2))-9=0



We calculate terms in parentheses: -(2x-(x+2)), so:

2x-(x+2)

We get rid of parentheses

2x-x-2

We add all the numbers together, and all the variables

x-2

Back to the equation:

-(x-2)



We get rid of parentheses

3x-x+2-9=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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