40=(-5/6(9+2x))

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Solution for 40=(-5/6(9+2x)) equation: 



40=(-5/6(9+2x))

We move all terms to the left:

40-((-5/6(9+2x)))=0



Domain of the equation: 6(9+2x)))!=0

x∈R



We add all the numbers together, and all the variables

-((-5/6(2x+9)))+40=0

We multiply all the terms by the denominator


-((-5+40*6(2x+9)))=0



We calculate terms in parentheses: -((-5+40*6(2x+9))), so:

(-5+40*6(2x+9))



We calculate terms in parentheses: +(-5+40*6(2x+9)), so:

-5+40*6(2x+9)

determiningTheFunctionDomain
40*6(2x+9)-5

Wy multiply elements

240x(2-5

Back to the equation:

+(240x(2-5)



We add all the numbers together, and all the variables

(240x(-3)



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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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240x(-3





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