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(x+4)+4(x)+10(x-1)=288
We move all terms to the left:
(x+4)+4(x)+10(x-1)-(288)=0
We add all the numbers together, and all the variables
4x+(x+4)+10(x-1)-288=0
We multiply parentheses
4x+(x+4)+10x-10-288=0
We get rid of parentheses
4x+x+10x+4-10-288=0
We add all the numbers together, and all the variables
15x-294=0
We move all terms containing x to the left, all other terms to the right
15x=294
x=294/15
x=19+3/5
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