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-5/6(9+2v)=40
We move all terms to the left:
-5/6(9+2v)-(40)=0
Domain of the equation: 6(9+2v)!=0We add all the numbers together, and all the variables
v∈R
-5/6(2v+9)-40=0
We multiply all the terms by the denominator
-40*6(2v+9)-5=0
Wy multiply elements
-240v(2-5=0
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