40+2(n-2)=8-3(2n+4)

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Solution for 40+2(n-2)=8-3(2n+4) equation: 



40+2(n-2)=8-3(2n+4)

We move all terms to the left:

40+2(n-2)-(8-3(2n+4))=0

We multiply parentheses

2n-(8-3(2n+4))-4+40=0



We calculate terms in parentheses: -(8-3(2n+4)), so:

8-3(2n+4)

determiningTheFunctionDomain
-3(2n+4)+8

We multiply parentheses

-6n-12+8

We add all the numbers together, and all the variables

-6n-4

Back to the equation:

-(-6n-4)



We add all the numbers together, and all the variables

2n-(-6n-4)+36=0

We get rid of parentheses

2n+6n+4+36=0

We add all the numbers together, and all the variables

8n+40=0

We move all terms containing n to the left, all other terms to the right

8n=-40

n=-40/8

n=-5

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