4/9y-5=27

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Solution for 4/9y-5=27 equation: 



4/9y-5=27

We move all terms to the left:

4/9y-5-(27)=0



Domain of the equation: 9y!=0

y!=0/9

y!=0

y∈R



We add all the numbers together, and all the variables

4/9y-32=0

We multiply all the terms by the denominator


-32*9y+4=0

Wy multiply elements

-288y+4=0

We move all terms containing y to the left, all other terms to the right

-288y=-4

y=-4/-288

y=1/72

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