7/3u-2/5=-2/5u+2

Solution for 7/3u-2/5=-2/5u+2 equation:

7/3u-2/5=-2/5u+2

We move all terms to the left:

7/3u-2/5-(-2/5u+2)=0


Domain of the equation: 3u!=0

u!=0/3

u!=0

u∈R



Domain of the equation: 5u+2)!=0

u∈R


We get rid of parentheses

7/3u+2/5u-2-2/5=0

We calculate fractions


875u/375u^2+6u/375u^2+(-6u)/375u^2-2=0

We multiply all the terms by the denominator


875u+6u+(-6u)-2*375u^2=0

We add all the numbers together, and all the variables

881u+(-6u)-2*375u^2=0

Wy multiply elements

-750u^2+881u+(-6u)=0

We get rid of parentheses

-750u^2+881u-6u=0

We add all the numbers together, and all the variables

-750u^2+875u=0

a = -750; b = 875; c = 0;
Δ = b2-4ac
Δ = 8752-4·(-750)·0
Δ = 765625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{765625}=875$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(875)-875}{2*-750}=\frac{-1750}{-1500}
=1+1/6
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(875)+875}{2*-750}=\frac{0}{-1500}
=0
$