8v-5+3(2v+1)=-2(v-5)

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Solution for 8v-5+3(2v+1)=-2(v-5) equation: 



8v-5+3(2v+1)=-2(v-5)

We move all terms to the left:

8v-5+3(2v+1)-(-2(v-5))=0

We multiply parentheses

8v+6v-(-2(v-5))+3-5=0



We calculate terms in parentheses: -(-2(v-5)), so:

-2(v-5)

We multiply parentheses

-2v+10

Back to the equation:

-(-2v+10)



We add all the numbers together, and all the variables

14v-(-2v+10)-2=0

We get rid of parentheses

14v+2v-10-2=0

We add all the numbers together, and all the variables

16v-12=0

We move all terms containing v to the left, all other terms to the right

16v=12

v=12/16

v=3/4

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