4/7(t)-1/14(t)=(t)-5/2

Solution for 4/7(t)-1/14(t)=(t)-5/2 equation:

4/7(t)-1/14(t)=(t)-5/2

We move all terms to the left:

4/7(t)-1/14(t)-((t)-5/2)=0


Domain of the equation: 7t!=0

t!=0/7

t!=0

t∈R



Domain of the equation: 14t!=0

t!=0/14

t!=0

t∈R


We add all the numbers together, and all the variables

4/7t-1/14t-(+t-5/2)=0

We get rid of parentheses

4/7t-1/14t-t+5/2=0

We calculate fractions


490t^2/392t^2-t+224t/392t^2+(-28t)/392t^2=0

We add all the numbers together, and all the variables

490t^2/392t^2-1t+224t/392t^2+(-28t)/392t^2=0

We multiply all the terms by the denominator


490t^2-1t*392t^2+224t+(-28t)=0

We add all the numbers together, and all the variables

490t^2+224t-1t*392t^2+(-28t)=0

Wy multiply elements

490t^2-392t^3+224t+(-28t)=0

We get rid of parentheses

490t^2-392t^3+224t-28t=0

We do not support etpression: t^3