4/5u+2/3+1/5u=u

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Solution for 4/5u+2/3+1/5u=u equation: 



4/5u+2/3+1/5u=u

We move all terms to the left:

4/5u+2/3+1/5u-(u)=0



Domain of the equation: 5u!=0

u!=0/5

u!=0

u∈R



We add all the numbers together, and all the variables

-1u+4/5u+1/5u+2/3=0

We calculate fractions

There is no solution for this equation

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