(3x-1)/3=(4x+1)/4

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Solution for (3x-1)/3=(4x+1)/4 equation: 



(3x-1)/3=(4x+1)/4

We move all terms to the left:

(3x-1)/3-((4x+1)/4)=0

We calculate fractions


3x/()+(-((4x+1)*3)/()=0



We calculate terms in parentheses: +(-((4x+1)*3)/(), so:

-((4x+1)*3)/(

We multiply all the terms by the denominator


-((4x+1)*3)



We calculate terms in parentheses: -((4x+1)*3), so:

(4x+1)*3

We multiply parentheses

12x+3

Back to the equation:

-(12x+3)



We get rid of parentheses

-12x-3

Back to the equation:

+(-12x-3)



We get rid of parentheses

3x/()-12x-3=0

We multiply all the terms by the denominator


3x-12x*()-3*()=0

We add all the numbers together, and all the variables

3x-12x*()=0

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