5(x-1)=-5+4(x-2)

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Solution for 5(x-1)=-5+4(x-2) equation: 



5(x-1)=-5+4(x-2)

We move all terms to the left:

5(x-1)-(-5+4(x-2))=0

We multiply parentheses

5x-(-5+4(x-2))-5=0



We calculate terms in parentheses: -(-5+4(x-2)), so:

-5+4(x-2)

determiningTheFunctionDomain
4(x-2)-5

We multiply parentheses

4x-8-5

We add all the numbers together, and all the variables

4x-13

Back to the equation:

-(4x-13)



We get rid of parentheses

5x-4x+13-5=0

We add all the numbers together, and all the variables

x+8=0

We move all terms containing x to the left, all other terms to the right

x=-8

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