4/5(10x+15)=4(2x+3)

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Solution for 4/5(10x+15)=4(2x+3) equation:



4/5(10x+15)=4(2x+3)
We move all terms to the left:
4/5(10x+15)-(4(2x+3))=0
Domain of the equation: 5(10x+15)!=0
x∈R
We multiply all the terms by the denominator
-((4(2x+3)))*5(10x+15)+4=0
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15
We calculate terms in parentheses: -((4(2x+3)))*5(10x+15), so:
(4(2x+3)))*5(10x+15

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