(9x+71)=(4x+112)

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Solution for (9x+71)=(4x+112) equation: 



(9x+71)=(4x+112)

We move all terms to the left:

(9x+71)-((4x+112))=0

We get rid of parentheses

9x-((4x+112))+71=0



We calculate terms in parentheses: -((4x+112)), so:

(4x+112)

We get rid of parentheses

4x+112

Back to the equation:

-(4x+112)



We get rid of parentheses

9x-4x-112+71=0

We add all the numbers together, and all the variables

5x-41=0

We move all terms containing x to the left, all other terms to the right

5x=41

x=41/5

x=8+1/5

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