-2(v-7)(-v+6)=0

Solution for -2(v-7)(-v+6)=0 equation:

-2(v-7)(-v+6)=0

We add all the numbers together, and all the variables

-2(v-7)(-1v+6)=0

We multiply parentheses ..

-2(-1v^2+6v+7v-42)=0

We multiply parentheses

2v^2-12v-14v+84=0

We add all the numbers together, and all the variables

2v^2-26v+84=0

a = 2; b = -26; c = +84;
Δ = b2-4ac
Δ = -262-4·2·84
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*2}=\frac{24}{4}
=6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*2}=\frac{28}{4}
=7
$