4z+6=-2z+48

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Solution for 4z+6=-2z+48 equation: 



4z+6=-2z+48

We move all terms to the left:

4z+6-(-2z+48)=0

We get rid of parentheses

4z+2z-48+6=0

We add all the numbers together, and all the variables

6z-42=0

We move all terms containing z to the left, all other terms to the right

6z=42

z=42/6

z=7

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