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4/3x+2=5x
We move all terms to the left:
4/3x+2-(5x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-5x+4/3x+2=0
We multiply all the terms by the denominator
-5x*3x+2*3x+4=0
Wy multiply elements
-15x^2+6x+4=0
a = -15; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·(-15)·4
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{69}}{2*-15}=\frac{-6-2\sqrt{69}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{69}}{2*-15}=\frac{-6+2\sqrt{69}}{-30} $
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