6x-(5-4x)=7+(x-5)

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Solution for 6x-(5-4x)=7+(x-5) equation: 



6x-(5-4x)=7+(x-5)

We move all terms to the left:

6x-(5-4x)-(7+(x-5))=0

We add all the numbers together, and all the variables

6x-(-4x+5)-(7+(x-5))=0

We get rid of parentheses

6x+4x-(7+(x-5))-5=0



We calculate terms in parentheses: -(7+(x-5)), so:

7+(x-5)

determiningTheFunctionDomain
(x-5)+7

We get rid of parentheses

x-5+7

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We add all the numbers together, and all the variables

10x-(x+2)-5=0

We get rid of parentheses

10x-x-2-5=0

We add all the numbers together, and all the variables

9x-7=0

We move all terms containing x to the left, all other terms to the right

9x=7

x=7/9

x=7/9

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