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(4x+80)(2x-12)=x
We move all terms to the left:
(4x+80)(2x-12)-(x)=0
We add all the numbers together, and all the variables
-1x+(4x+80)(2x-12)=0
We multiply parentheses ..
(+8x^2-48x+160x-960)-1x=0
We get rid of parentheses
8x^2-48x+160x-1x-960=0
We add all the numbers together, and all the variables
8x^2+111x-960=0
a = 8; b = 111; c = -960;
Δ = b2-4ac
Δ = 1112-4·8·(-960)
Δ = 43041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(111)-\sqrt{43041}}{2*8}=\frac{-111-\sqrt{43041}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(111)+\sqrt{43041}}{2*8}=\frac{-111+\sqrt{43041}}{16} $
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