4/3(7c)=12

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Solution for 4/3(7c)=12 equation: 



4/3(7c)=12

We move all terms to the left:

4/3(7c)-(12)=0



Domain of the equation: 37c!=0

c!=0/37

c!=0

c∈R



We multiply all the terms by the denominator


-12*37c+4=0

Wy multiply elements

-444c+4=0

We move all terms containing c to the left, all other terms to the right

-444c=-4

c=-4/-444

c=1/111

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