2/3x+1=3(x-4)

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Solution for 2/3x+1=3(x-4) equation: 



2/3x+1=3(x-4)

We move all terms to the left:

2/3x+1-(3(x-4))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We multiply all the terms by the denominator


-((3(x-4)))*3x+1*3x+2=0

Wy multiply elements

-((3(x-4)))*3x+3x+2=0

We add all the numbers together, and all the variables

3x-((3(x-4)))*3x+2=0

We move all terms containing x to the left, all other terms to the right

3x-((3(x-4)))*3x=-2

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