-4(n-2)=3(3-n)+7

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Solution for -4(n-2)=3(3-n)+7 equation: 



-4(n-2)=3(3-n)+7

We move all terms to the left:

-4(n-2)-(3(3-n)+7)=0

We add all the numbers together, and all the variables

-4(n-2)-(3(-1n+3)+7)=0

We multiply parentheses

-4n-(3(-1n+3)+7)+8=0



We calculate terms in parentheses: -(3(-1n+3)+7), so:

3(-1n+3)+7

We multiply parentheses

-3n+9+7

We add all the numbers together, and all the variables

-3n+16

Back to the equation:

-(-3n+16)



We get rid of parentheses

-4n+3n-16+8=0

We add all the numbers together, and all the variables

-1n-8=0

We move all terms containing n to the left, all other terms to the right

-n=8

n=8/-1

n=-8

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