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4/10x=2/3x-14
We move all terms to the left:
4/10x-(2/3x-14)=0
Domain of the equation: 10x!=0
x!=0/10
x!=0
x∈R
Domain of the equation: 3x-14)!=0We get rid of parentheses
x∈R
4/10x-2/3x+14=0
We calculate fractions
12x/30x^2+(-20x)/30x^2+14=0
We multiply all the terms by the denominator
12x+(-20x)+14*30x^2=0
Wy multiply elements
420x^2+12x+(-20x)=0
We get rid of parentheses
420x^2+12x-20x=0
We add all the numbers together, and all the variables
420x^2-8x=0
a = 420; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·420·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*420}=\frac{0}{840} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*420}=\frac{16}{840} =2/105 $
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