4(3k-5)=2(46+3k)

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Solution for 4(3k-5)=2(46+3k) equation: 



4(3k-5)=2(46+3k)

We move all terms to the left:

4(3k-5)-(2(46+3k))=0

We add all the numbers together, and all the variables

4(3k-5)-(2(3k+46))=0

We multiply parentheses

12k-(2(3k+46))-20=0



We calculate terms in parentheses: -(2(3k+46)), so:

2(3k+46)

We multiply parentheses

6k+92

Back to the equation:

-(6k+92)



We get rid of parentheses

12k-6k-92-20=0

We add all the numbers together, and all the variables

6k-112=0

We move all terms containing k to the left, all other terms to the right

6k=112

k=112/6

k=18+2/3

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