3(2x-3)+12=4(x-2)-(3x+4)

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Solution for 3(2x-3)+12=4(x-2)-(3x+4) equation: 



3(2x-3)+12=4(x-2)-(3x+4)

We move all terms to the left:

3(2x-3)+12-(4(x-2)-(3x+4))=0

We multiply parentheses

6x-(4(x-2)-(3x+4))-9+12=0



We calculate terms in parentheses: -(4(x-2)-(3x+4)), so:

4(x-2)-(3x+4)

We multiply parentheses

4x-(3x+4)-8

We get rid of parentheses

4x-3x-4-8

We add all the numbers together, and all the variables

x-12

Back to the equation:

-(x-12)



We add all the numbers together, and all the variables

6x-(x-12)+3=0

We get rid of parentheses

6x-x+12+3=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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