(7a=3)+(-a-5)=-16

Solution for (7a=3)+(-a-5)=-16 equation:

(7a=3)+(-a-5)=-16

We move all terms to the left:

(7a-(3)+(-a-5))=0

We add all the numbers together, and all the variables

(7a-3+(-1a-5))=0


We calculate terms in parentheses: +(7a-3+(-1a-5)), so:

7a-3+(-1a-5)

determiningTheFunctionDomain
7a+(-1a-5)-3

We get rid of parentheses

7a-1a-5-3

We add all the numbers together, and all the variables

6a-8

Back to the equation:

+(6a-8)


We get rid of parentheses

6a-8=0

We move all terms containing a to the left, all other terms to the right

6a=8

a=8/6

a=1+1/3