4/(x+1)=2/(2x-3)

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Solution for 4/(x+1)=2/(2x-3) equation: 



4/(x+1)=2/(2x-3)

We move all terms to the left:

4/(x+1)-(2/(2x-3))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (2x-3))!=0

x∈R



We calculate fractions


8x/((x+1)*(2x-3)))+(-(2*(x+1))/((x+1)*(2x-3)))=0



We calculate terms in parentheses: -(2*(x+1))/((x+1)*(2x-3))), so:

2*(x+1))/((x+1)*(2x-3))

We multiply all the terms by the denominator


2*(x+1))

We multiply parentheses

2x+

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

-2x+8x/((x+1)*(2x-3)))+(=0

We multiply all the terms by the denominator


-2x*((x+1)*(2x-3)))+(+8x=0

We add all the numbers together, and all the variables

8x-2x*((x+1)*(2x-3)))+(=0

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