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3(2x+1)=5(2x-5)=
We move all terms to the left:
3(2x+1)-(5(2x-5))=0
We multiply parentheses
6x-(5(2x-5))+3=0
We calculate terms in parentheses: -(5(2x-5)), so:We get rid of parentheses
5(2x-5)
We multiply parentheses
10x-25
Back to the equation:
-(10x-25)
6x-10x+25+3=0
We add all the numbers together, and all the variables
-4x+28=0
We move all terms containing x to the left, all other terms to the right
-4x=-28
x=-28/-4
x=+7
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