4x*4x=196

Solution for 4x*4x=196 equation:

4x*4x=196

We move all terms to the left:

4x*4x-(196)=0

Wy multiply elements

16x^2-196=0

a = 16; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·16·(-196)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*16}=\frac{-112}{32}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*16}=\frac{112}{32}
=3+1/2
$