4-3(x+12)=2(x-5)

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Solution for 4-3(x+12)=2(x-5) equation: 



4-3(x+12)=2(x-5)

We move all terms to the left:

4-3(x+12)-(2(x-5))=0

We multiply parentheses

-3x-(2(x-5))-36+4=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

-3x-(2x-10)-32=0

We get rid of parentheses

-3x-2x+10-32=0

We add all the numbers together, and all the variables

-5x-22=0

We move all terms containing x to the left, all other terms to the right

-5x=22

x=22/-5

x=-4+2/5

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