(x+4)2+12=28

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Solution for (x+4)2+12=28 equation: 



(x+4)2+12=28

We move all terms to the left:

(x+4)2+12-(28)=0

We add all the numbers together, and all the variables

(x+4)2-16=0

We multiply parentheses

2x+8-16=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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