(x+3)/7=(x-3)/6

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Solution for (x+3)/7=(x-3)/6 equation: 



(x+3)/7=(x-3)/6

We move all terms to the left:

(x+3)/7-((x-3)/6)=0

We calculate fractions


x/()+(-((x-3)*7)/()=0



We calculate terms in parentheses: +(-((x-3)*7)/(), so:

-((x-3)*7)/(

We multiply all the terms by the denominator


-((x-3)*7)



We calculate terms in parentheses: -((x-3)*7), so:

(x-3)*7

We multiply parentheses

7x-21

Back to the equation:

-(7x-21)



We get rid of parentheses

-7x+21

Back to the equation:

+(-7x+21)



We get rid of parentheses

x/()-7x+21=0

We multiply all the terms by the denominator


x-7x*()+21*()=0

We add all the numbers together, and all the variables

x-7x*()=0

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