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4(1-3a)+2a=2(2-5a)
We move all terms to the left:
4(1-3a)+2a-(2(2-5a))=0
We add all the numbers together, and all the variables
4(-3a+1)+2a-(2(-5a+2))=0
We add all the numbers together, and all the variables
2a+4(-3a+1)-(2(-5a+2))=0
We multiply parentheses
2a-12a-(2(-5a+2))+4=0
We calculate terms in parentheses: -(2(-5a+2)), so:We add all the numbers together, and all the variables
2(-5a+2)
We multiply parentheses
-10a+4
Back to the equation:
-(-10a+4)
-10a-(-10a+4)+4=0
We get rid of parentheses
-10a+10a-4+4=0
We add all the numbers together, and all the variables
=0
a=0/1
a=0
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